# Boolean algebra: (A'+B)(A+C)

I have a little problem with this expression:

x = (A'+B)(A+C)

I know it can be simplified to:

A'C+AB

since ive used some software to simplify it, but i simply can't see how it is done.This is what i've done so far:

(A'+B)(A+C) =>

A'A + AB + A'C + BC =>

0 + AB + A'C + BC =>

AB + A'C + BC

I just fail to see how i can do this differently and get to the correct result.